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December 20, 2014

December 20, 2014

Posted by **Sam** on Thursday, October 7, 2010 at 4:37pm.

I think it should be 30m/s cos 35/9.8.

If not correct please let me know what formula to use.

- Physics-Just need a formula, please and check -
**Sam**, Thursday, October 7, 2010 at 5:05pmCan someone please just check this problem and let me know if its wrong and the correct formula

Thank you

- Physics -
**bobpursley**, Thursday, October 7, 2010 at 5:10pmWell, it is correct.

- Physics -
**drwls**, Thursday, October 7, 2010 at 5:11pmYour formula is incorrect. Dividing the horizontal velocity component by g does not get you the time of flight. Note that, with your formula, the time of flight would be zero if the ball were hit straight up.

The time of flight, T, is the time it takes the ball to go up and then come back down. Those two times are equal.

T = 2 V sin35/g

- Physics -
**bobpursley**, Thursday, October 7, 2010 at 5:13pmdrwls is correct.

- Physics-I'm really confused with two different answers -
**Sam**, Thursday, October 7, 2010 at 5:16pmSo I should say

2 times (20sin35)/9.8 = 2.34

I'm really confused because one said it's correct and you said what I did is wrong-Please help

- Physics -
**bobpursley**, Thursday, October 7, 2010 at 5:17pmreread.

- Physics -
**drwls**, Thursday, October 7, 2010 at 7:10pmThe time of flight is 2*(30sin35)/9.8 = 3.51 seconds.

I do not understand why the question began with a statement that the ball is hit for 0.2 s. You do not need that bit of information to answer the question about the time of flight. You could use it and the ball's momentum leaving the club face to calculate the average force of the club on the ball.

- Physics -
**Sam**, Thursday, October 7, 2010 at 8:04pmThank you, I appreciate it-I understand it now

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