Posted by **Andrew** on Thursday, October 7, 2010 at 4:06pm.

An elevator and its load have a combined mass of 1700 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 13 m/s, is brought to rest with constant acceleration in a distance of 43 m.

- physics -
**drwls**, Thursday, October 7, 2010 at 5:06pm
The cable tension will increase to

T = M(g+a)

when the elevator is slowing down at deceleration rate a.

You can get a from the relation

V^2/2 = a X

where X is the stopping distance, and V is the initial velocity.

- physics -
**praj**, Saturday, April 11, 2015 at 8:44am
6089

- physics -
**peter**, Tuesday, March 29, 2016 at 7:04am
169/2=a*43

84.5=a*43

a=84.5/43

a=1.965

T=M(g+a)

T=1700(-9.8+1.965)

T=1700*(-7.835)

T=-13,319.5

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