posted by Andrew on .
An elevator and its load have a combined mass of 1700 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 13 m/s, is brought to rest with constant acceleration in a distance of 43 m.
The cable tension will increase to
T = M(g+a)
when the elevator is slowing down at deceleration rate a.
You can get a from the relation
V^2/2 = a X
where X is the stopping distance, and V is the initial velocity.