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February 28, 2015

February 28, 2015

Posted by **Calculus** on Thursday, October 7, 2010 at 3:49pm.

If you find g'(t) you just get 5 so would there be no critical numbers? Or am I missing something?

- Calculus -
**Reiny**, Thursday, October 7, 2010 at 5:30pmyour graph consists of two straight lines

y = 5t-7 and y = -5t + 7 where you only want the part above the t-axis (x-axis normally)

The two lines meet on the t-axis at the point (7/5 , 0)

That point is called a "cusp" and it would be the only critical number.

Differentiating the function would be over-kill since when you find the derivative of a straight line, you just get the slope, which we knew already anyway.

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