Posted by Calculus on .
Find the critical numbers of the function g(t)=5t7
If you find g'(t) you just get 5 so would there be no critical numbers? Or am I missing something?

Calculus 
Reiny,
your graph consists of two straight lines
y = 5t7 and y = 5t + 7 where you only want the part above the taxis (xaxis normally)
The two lines meet on the taxis at the point (7/5 , 0)
That point is called a "cusp" and it would be the only critical number.
Differentiating the function would be overkill since when you find the derivative of a straight line, you just get the slope, which we knew already anyway.