Posted by Tim on .
A 6-kg clay ball is thrown directly against a perpendicular brick wall at a velocity of 22 m/s and shatters into three pieces, which all fly backward, as shown in the figure. The wall exerts a force on the ball of 2430 N for 0.1 s. One piece of mass 2 kg travels backward at a velocity of 15 m/s and an angle of 32° above the horizontal. A second piece of mass 1 kg travels at a velocity of 7 m/s and an angle of 28° below the horizontal. What is the velocity of the third piece? (Let up be the +y positive direction and to the right be the +x direction.)
Initial momentum = Final momentum + impulse delvered by the wall.
You have all the information you need to solve for the momentum of the third pice.
Assume the force provided at the wall is in the -x direction