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April 18, 2014

April 18, 2014

Posted by **julie** on Wednesday, October 6, 2010 at 11:25pm.

- science physics -
**Steven**, Thursday, October 7, 2010 at 12:47amThe speed at which the two objects are approaching each other (from the trains' perspective) is 95 km/h (x 2) = 190 km/h.

If they are 7.5 km apart at first, you can set up a proportion:

190 km 7.5 km

------ = ---------

1 hr x hr

Cross-multiply the terms and set them equal to each other.

(190 km)(x hr) = (7.5 km)(1 hr)

Divide both sides by (190 km).

(190 km)(x hr) = (7.5 km)(1 hr)

-------------- --------------

190 km 190 km

x hr = (7.5 kmh)/190 km

x hr = 0.03947368421 hr.

(sig figs = 0.039 hr)

The unit of hr. may not be very useful in this case, so let's convert hrs to min using dimensional analysis:

0.03947368 hr 60 min

------------- x ------------

1 1 hr

= 2.36 minutes

(sig figs = 2.4 minutes)

Hope this helps!

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