Posted by **Sasha** on Wednesday, October 6, 2010 at 9:35pm.

find h'(2) given that f(2) = -3, g(2) = 4, f'(2)= -2 and g'(2)= 7.

A. h(x) = 5f(x) - 4g(x)

B. h(x) = f(x)g(x)

C. h(x) = f(x)/g(x)

D. h(x) = g(x)/ 1+ f(x)

- calculus -
**Joshie**, Wednesday, October 6, 2010 at 10:04pm
simply chart it out.

f(x) g(x) f'(x) g'(x)

2| -3 4 -2 7

then plug them into the equations.

A. (5)-3 - 4(4)

-15 - 16 = -31

B. (-3)4 = -12

C. -3/4

D. 4/1-3

= 4/-2 = -2

- calculus -
**Joshie**, Wednesday, October 6, 2010 at 10:06pm
well the chart didn show up right but when x = 2 then

f(x) = -3

g(x) = 4

f'(x) = -2

g'(x) = 7

then plug them into the equations.

A. (5)-3 - 4(4)

-15 - 16 = -31

B. (-3)4 = -12

C. -3/4

D. 4/1-3

= 4/-2 = -2

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