pitcher throws a ball for 1.98m. the balls mass is .145kg. what is the force on the ball by the pitcher?
To calculate the force on the ball thrown by the pitcher, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m * a).
In this case, we know the mass of the ball (m = 0.145 kg) but we need to find the acceleration. To do that, we can use the equations of motion. We know that distance traveled (d) is 1.98 m and we need to find the acceleration (a). We also know that the initial velocity (u) is usually 0 for a ball thrown from rest.
The equation that relates these variables is:
d = ut + (1/2)at^2,
where:
d = distance (1.98 m),
u = initial velocity (0 m/s),
a = acceleration (unknown),
t = time taken.
Since the initial velocity is 0, the equation simplifies to:
d = (1/2)at^2.
Now we can solve for acceleration (a):
2d = at^2,
a = (2d) / t^2.
Unfortunately, we don't have information about the time taken (t) to cover the distance. As a result, we cannot determine the acceleration and therefore, the force on the ball without the time data.