Posted by **michelle** on Wednesday, October 6, 2010 at 2:51pm.

A skateboarder, starting from rest, rolls down a 14.0-m ramp. When she arrives at the bottom of the ramp her speed is 7.40 m/s.

(a) Determine the magnitude of her acceleration, assumed to be constant.

(b) If the ramp is inclined at 20.5° with respect to the ground, what is the component of her acceleration that is parallel to the ground?

please help! it would be much appreciated!!

- posting again! please help!! physics -
**Henry**, Thursday, October 7, 2010 at 9:25pm
a. V^2 = 2ad,

2ad = V^2,

2a*14 = (7.4)^2,

28a = 54.76,

a = 54.76/28 = 1.96 m/s^2.

b. a(hor) = 1.96*cos20.5 = 1.83 m/s^2.

## Answer this Question

## Related Questions

- Physics - A skateboarder, starting from rest, rolls down a 12.5-m ramp. When she...
- physics - A skateboarder, starting from rest, rolls down a 14.0-m ramp. When she...
- physics!! - A skateboarder, starting from rest, rolls down a 14.0-m ramp. When ...
- physics - A skateboarder, starting from rest, rolls down a 13.4-m ramp. When she...
- physics - A skateboarder, starting from rest, rolls down a 13.9-m ramp. When she...
- Physics - I need help with this question...A skateboarder, starting from rest, ...
- physics - A skateboarder, starting from rest, rolls down a 11.5-m ramp. When she...
- physics mechanical energy - A skateboarder with mass ms = 42 kg is standing at ...
- physics - A skateboarder with mass ms = 42 kg is standing at the top of a ramp ...
- PHYSICS (please help) - A solid, uniform disk of radius 0.250 m and mass 51.1 kg...

More Related Questions