A skateboarder, starting from rest, rolls down a 14.0-m ramp. When she arrives at the bottom of the ramp her speed is 7.40 m/s.
(a) Determine the magnitude of her acceleration, assumed to be constant.
(b) If the ramp is inclined at 20.5° with respect to the ground, what is the component of her acceleration that is parallel to the ground?
please help! it would be much appreciated!!
posting again! please help!! physics - Henry, Thursday, October 7, 2010 at 9:25pm
a. V^2 = 2ad,
2ad = V^2,
2a*14 = (7.4)^2,
28a = 54.76,
a = 54.76/28 = 1.96 m/s^2.
b. a(hor) = 1.96*cos20.5 = 1.83 m/s^2.