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PHYSICS ---HELP!

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A 120-kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 400 N. For the first 17 m the floor is frictionless, and for the next 17 m the coefficient of friction is 0.34. What is the final speed of the crate?

  • PHYSICS ---HELP! - ,

    Kinetic energy gained during the frictionless interval is 400 N * 17 m = 6800 J. When there is friction, the net force pulling the weight is 400 N - M*g*mu = 400 - 399.8 N = 0.2 N. Additional kinetic energy gain is limited to 0.2N*17m = 3.4 J

    The rest of the work done ends up as heat.

    Final kientic energy is 6803 J. Use that for the final velocity

  • PHYSICS ---HELP! - ,

    how would I show that in m/s?

  • PHYSICS ---HELP! - ,

    you use 1/2*m*v^2

  • PHYSICS ---HELP! - ,

    the answer is = 1

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