Posted by mike on Tuesday, October 5, 2010 at 10:58pm.
there are two tangents lines to the curve f(x) = 3x^2 that pass through the point p =0,1 find the x coordinates of the point where the tangents line intersect the curve

calculus  Reiny, Tuesday, October 5, 2010 at 11:08pm
The point (0,1) lies in the "interior" of the parabola
y = 3x^2.
There is no tangent to the curve that will pass through (0,1).
check your typing. 
calculus  mike, Tuesday, October 5, 2010 at 11:21pm
there are two tangents lines to the curve f(x) = 3x^2 that pass through the point p =0,1 find the x coordinates of the point where the tangents line intersect the curve, please show working.

calculus  Reiny, Tuesday, October 5, 2010 at 11:28pm
ahhh, now it makes sense.
let the point of contact be (a,b)
slope of tangent by the grade 9 way = (b+1)/a
slope of tangent by Calculus is
dy/dx = 6x
so at the point (a,b), slope = 6a
then 6a = (b+1)/a
6a^2 = b+1
but since (a,b) lies on the curve, b = 3a^2
so
6a^2 = 3a^2 + 1
a^2 = 1/3
a = ± 1/√3
so the x coordinates of the two tangents are 1/√3 and 1/√3 
calculus  mike, Tuesday, October 5, 2010 at 11:39pm
find the equation of the tangent line of the curve y=root x divideed by x+1 at the point p = 2, root 2 divided by 3. show working please.

calculus  mike, Wednesday, October 6, 2010 at 10:54am
find the equation of the tangent line to the curve y = 2√2/x+1 at the point p=1,2/3.please show working. i would appreciate if you do it before 12:05pm today

calculus  mike, Tuesday, October 19, 2010 at 11:18pm
use implcit differenciation to find an eqaution of both the tangent line to the ellipse:
2x^2 + 4y^2 = 36
that passes through the points: 14,3