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For an interesting physics field trip, we visit Tahquamenon Falls in the Upper Peninsula. We measure the horizontal speed of the water at the top of the falls to be 3.98 m/s. How far vertically below the top edge of the falls does the velocity vector of the water point downward at a 55.7 degrees angle below the horizontal?

worded pretty confusing to me.. but it does give a little hint after missing it.
"Find the appropriate vertical component of velocity to give the downward angle. How far down does an object have to fall to gain that speed?"
please explain and give equation

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