Saturday
April 19, 2014

Homework Help: Chemistry

Posted by Anonymous on Tuesday, October 5, 2010 at 7:19pm.

The equilibrium constant for HI decomposition at 500 C is 5.810-3.

2HI(g) > H2(g) + I2(g)

At that temperature reactants and products are gaseous. (There is no change in the total number of moles, so Kc = Kp.)
A sample of 0.49 mol of HI is placed in a 1.00 L vessel which is then heated to 500 C. When equilibrium is reached, what is the molar concentration of H2? (Give units).
[H2] = 0.032 M

Now I cant figure out how to fine the concentrations of I2 and HI.
I keep getting for I2=.035M and for HI=.46M

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - The equilibrium constant for HI decomposition at 500 C is 5.810-3...
chemistry - At a certain temperature, the Equilibrium constant, Kc, for this ...
Chemistry - The decomposition of HI(g) is represented by the equation: 2HI(g) &...
Idontgetit - The value of the equilibrium constant (Kp) as represented by the ...
Chemistry - For the reaction: H2(g) + I2(g) 2HI(g) , Kc = 12.3 at some ...
Chemistry - At a certain temperature, the equilibrium constant, Kc, for this ...
Chemistry - At a certain temperature, the equilibrium constant, Kc, for this ...
chemistry - the equilibrium system shown below was analyzed and the ...
chemistry - H2+I2->2HI If 3 moles of H2, I2, and HI are in a 3L flask, what ...
Chemistry II - At a certain temperature, Kc = 33 for the reaction: H2(g) + I2(g...

Search
Members