Homework Help: Physics

Posted by David on Tuesday, October 5, 2010 at 5:48pm.

In a cyclotron (one type of particle accelerator), a deuteron (of mass 2.00 u) reaches a final speed of 8.4% of the speed of light while moving in a circular path of radius 0.551 m. What magnitude of magnetic force is required to maintain the deuteron in a circular path?

Physics - bobpursley, Tuesday, October 5, 2010 at 6:57pm
centripetal force= magnetic force

m v^2/r=Bqv

B= m v/qr

at .084 c, I would first work it ignoring relativistic changes in mass, then rework it considering them.

mass m is not in u units, but in kg.
Physics - LOLLLL, Sunday, August 21, 2011 at 12:13am
OK SO F=MA

M= 2.00U --> kg --> 3.32107773 × 10^-27 kg

A= v^2/r

v=8.4% speed light, => (299792458)*8.4/100...
Plug into F=MA

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