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December 21, 2014

December 21, 2014

Posted by **Hannah** on Tuesday, October 5, 2010 at 5:39pm.

a) x intercept = 3 y intercept=-2

I am really not sure how to start here.

b) vertical line containing (5,-1)

Would it be y=5x-1?

c) parallel to the line 3x-4y=5 and containing the points (3,-6) .

I know that the line has to have the same slope as the one about.

d) Find the slope and y intercept of the line 4x-6y=-3

To find the y value would i plug in zero for the x and solve? And then I can find the slope?

Thank You for helping!!

- Math -
**Henry**, Wednesday, October 6, 2010 at 5:36pma. y = 0 at the x intercept,

x = 0 at the y intercept,

Therefore: (3 , 0) , (0 , -2),

Slope = (-2-0) / (0-3) = -2/-3 = 2/3,

y = mx + b,

0 = (2/3)*3 + b,

0 = 6/3 + b,

b = -2.

Eq: y = (2/3)x -2.

b. On a vertical line, x is the same for all values of y.In other words, x is constant. On the given vertical line,x = 5. Therefore, x = 5 for all values of y:

(5 , -1) , (5 , 2) , (5 , 4). All of these points are on the required vertical line.

Eq: x = 5.

c. Given: 3x - 4y = 5, (3 , -6).

m1 = m2 = -A/B = -3/-4 = 3/4,

Y = mx + b,

-6 = (3/4)*3 + b,

-6 = 9/4 + b,

-6 -9/4 = b,

-24/4 -9/4 = b,

b = -33/4,

Eq: y = (3/4)x - 33/4.

d. Given: 4x - 6y = -3.

Slope = -A/B = -4/-6 = 4/6 = 2/3,

Let x = 0:,

4*0 - 6y = -3,

-6y = -3,

y = -3/-6 = 3/6 = 1/2 = y-intercept

.

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