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August 31, 2014

August 31, 2014

Posted by **Hannah** on Tuesday, October 5, 2010 at 3:35pm.

y^2 - x - 4 = 0

I got (-4,0) and (0,2) for the intercepts.

-y^2 - x - 4 = 0 Is not symmetrical to the x axis, correct?

y^2-(-x) - 4 = 0 Is not symmetrical to the y axis, correct?

-y^2 + x - 4 = 0 Is not symmetrical to the origin, correct?

- Math(Please check! Thank You) -
**Henry**, Tuesday, October 5, 2010 at 8:50pmSince x is in the 1st degree and y is in the 2nd degree, this is an x parabola. So we solve for x and get:

x = y^2 - 4,

We have the difference of 2 squares:

(y + 2) (y - 2) = 0,

y + 2 = 0,

y = -2.

y - 2 = 0,

y = 2.

Solution set: y = -2, and y = 2.

The x parabola is symmetric to the x

axis.

The y-intercepts are -2, and 2.

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