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Posted by **Justin** on Tuesday, October 5, 2010 at 3:28pm.

a)How high above the ground is the highest point that the skateboarder reaches?

b) When the skateboarder reaches the highest point, how far is this point horizontally from the end of the ramp?

- Physics -
**bobpursley**, Tuesday, October 5, 2010 at 3:43pmbreak the initial vertical velocity into vertical, and horizontal components

vertical Viv=6.5sin59

horizontalVih=6.5cos59

at the highest point, the vertical velocity will be zero.

vf=viv-g*t

t=viv/g

now use that time in

h(t)=hi+viv*t-4.9t^2

how far?

distance=vih*t

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