Posted by Amber on Tuesday, October 5, 2010 at 1:38pm.
Let v(x) = e^2x + 1
dv/dx= 2 e^2x
Let u(v) = tan^3 v
f(x) = u[(v(x)]
df/dx = du/dv * dv/dx
For du/dv, let f(g) = g^3 and
g(v) = tan v
u = f{g(v)}
du/dv = df/dg * dg/dv = 3 g^2 * sec^2(v)
= 3 tan^2v*sec^2(v)
df/dx= 2e^(2x)*3tan^2v*sec^2(v)
Substitute e^2x +1 for v for the derivative imn terms of x.
Related Questions
calculus - Differentiate e^(2x^3+x) X tan(x^2) tan e^x / ln(x^6/2-3x+3e) cos(tan...
calculus - So I am suppose to evaulate this problem y=tan^4(2x) and I am ...
Calculus - I think I have the correct answers for the following problems. For ...
Calc - intergral of (x^3 -4x + 3)/(2x) dx would this be ln abs(x^3-4x+3) + C? I ...
Maths Calculus Derivatives - Find the first derivative for the following ...
Pre Calculus - I keep trying to solve this by factring but I can't seem to ...
Calculus - How do I differentiate ln (2X^2 - 12X + Y^2 -10Y) and the second ...
Calculus AP - I'm doing trigonometric integrals i wanted to know im doing ...
Calculus - I'm having problems with this one. Can't get the right answer...
calculus - f(x) = x^2 g(x) = e^2x h(x) = ln(2x) which function is increasing the...
For Further Reading
