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September 1, 2014

September 1, 2014

Posted by **Amber** on Tuesday, October 5, 2010 at 1:38pm.

- calculus -
**drwls**, Tuesday, October 5, 2010 at 8:28pmLet v(x) = e^2x + 1

dv/dx= 2 e^2x

Let u(v) = tan^3 v

f(x) = u[(v(x)]

df/dx = du/dv * dv/dx

For du/dv, let f(g) = g^3 and

g(v) = tan v

u = f{g(v)}

du/dv = df/dg * dg/dv = 3 g^2 * sec^2(v)

= 3 tan^2v*sec^2(v)

df/dx= 2e^(2x)*3tan^2v*sec^2(v)

Substitute e^2x +1 for v for the derivative imn terms of x.

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