Sunday

January 25, 2015

January 25, 2015

Posted by **Amber** on Tuesday, October 5, 2010 at 1:38pm.

- calculus -
**drwls**, Tuesday, October 5, 2010 at 8:28pmLet v(x) = e^2x + 1

dv/dx= 2 e^2x

Let u(v) = tan^3 v

f(x) = u[(v(x)]

df/dx = du/dv * dv/dx

For du/dv, let f(g) = g^3 and

g(v) = tan v

u = f{g(v)}

du/dv = df/dg * dg/dv = 3 g^2 * sec^2(v)

= 3 tan^2v*sec^2(v)

df/dx= 2e^(2x)*3tan^2v*sec^2(v)

Substitute e^2x +1 for v for the derivative imn terms of x.

**Answer this Question**

**Related Questions**

calculus - Differentiate e^(2x^3+x) X tan(x^2) tan e^x / ln(x^6/2-3x+3e) cos(tan...

calculus - a billboard 20ft tall is located on top of a building with its lower ...

Calculus - I think I have the correct answers for the following problems. For ...

calculus - Differentiate the following function. f (x) = 6 x 2 sin(x)tan(x) ...

calculus - can anyone tell me if tan-1x= 1 over tan x? No. They are different. ...

trigo help! - 1. differentiate cos(3/x) 2. differentiate sin(4/x) 3. ...

Calculus - I'm having problems with this one. Can't get the right answer. ...

calculus - If limit as delta x approaches 0 of tan(0+Δx)-tan(0)/Δx =1 ...

calculus - So I am suppose to evaulate this problem y=tan^4(2x) and I am ...

Calculus - How do I differentiate ln (2X^2 - 12X + Y^2 -10Y) and the second ...