October 4, 2015

Homework Help: chemistry

Posted by Serenity on Tuesday, October 5, 2010 at 11:28am.

Hi, I posted this question earlier but still need some help:

1.3188g of antacid is weighed and mixed with 75.00mL of excess 0.1746 M HCl. The excess acid required 27.20 mL of 0.09767 M NaOH for back titration. Calculate the neutralizing power of the antacid in terms of mmol H+ per gram of antacid.

So far I have:
mmoles HCl added= 0.1746 x 75.00mL= 13.095 moles

mmles NaOH titrate the excess acid= 27.20 mL x 0.09767 M NaOH= 2.6566 moles

But don't know what to do from here.
Please help asap.

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