Posted by Promise on Tuesday, October 5, 2010 at 9:44am.
Since it is a conducting metal, there is no net E field. Negative charge accumulates at one end of the rod, while the rod moves, but there is also a magnetic force on electrons that opposes the field created by displaced electron charge.
If a closed circuit were formed, so that electrons were free to move in a current loop, the EMF (E-field times length) would double if the length of the rod doubled. The E-field would stay the same. I believe the value would be B * (V/c), but am not sure.
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