physics
posted by Kim on .
A 120kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 400 N. For the first 17 m the floor is frictionless, and for the next 17 m the coefficient of friction is 0.34. What is the final speed of the crate?

Use
F=ma to find the acceleration
and
v²u²=2aS
to find the final velocity v from an initial velocity u over a distance of S and acceleration a.
F=400 N for the first 17m
and F=400μmg for the next 17m, where μ is the coefficient of kinetic friction.
Post what you get for a check if you wish. 
0 j