Post a New Question


posted by on .

A projectile is fired at an angle of 60degree with the horizontal and with the initial velocity 80m/s calculate (a) the time of flight(b)time to reach maximum height(c)it range(d)the velocity of projection 2seconds after been fired

  • Physics - ,

    a)T=2u sin60/g=13.85s

  • Physics - ,

    For a, using g = 9.80 m/s^2, I get
    T = 2 u sin 60/g = 14.14 s. If I use g = 9.81 m/s^2, I get 14.12 s.

    This leads to slightly different answers to b) and c) than were obtained by vishesh

    c) Use
    R = u cos 60 * T

  • Physics - ,

    A projectile is fired from ground level with an initial velocity of 50m/s and an initial angle of 30degree. Assuming g= 9.8 m/s*2, find:
    (a) The projectile total time of flight.
    (b) The maximum height attained
    (c) The total horizontal traveled
    (d) The final horizontal and vertical velocities just before it hits the ground

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question