Posted by rick on Tuesday, October 5, 2010 at 2:01am.
You'll need the logical equivalence:
p → q ≡ !p ∨ q
so
!p → (q→r)
≡ p ∨ (!q ∨ r)
From here, use the commutative properties to rearrange the expression and apply the equivalence (of →) again to get the desired result.
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