posted by chuck on .
Consider the circuit shown in the figure below. Use the following as necessary: R1 = 11.00 Ù, R2 = 1.40 Ù, and V = 6.00 V.
(a) Calculate the equivalent resistance of the R1 and 5.00 Ù resistors connected in parallel.
(b) Using the result of part (a), calculate the combined resistance of the R1, 5.00 Ù, and 4.00 Ù resistors.
(c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00 Ù resistor.
(d) Combine the equivalent resistance found in part (c) with the R2 resistor.
(e) Calculate the total current in the circuit.
(f) What is the voltage drop across the R2 resistor?
(g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00 Ù resistor.
(h) Calculate the current in the 3.00 Ù resistor.
Sorry, without the accompanying figure, it is quite difficult to guess what the circuit is like.
See if you can post a link, although it is not always possible.