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October 24, 2014

October 24, 2014

Posted by **sh** on Tuesday, October 5, 2010 at 12:41am.

(2,infinity] ?

- math -
**MathMate**, Tuesday, October 5, 2010 at 1:42pmThe proposed answer is good for √(x-2).

However, since the denominator becomes negative between -2 and 1, the expression in the square-root radical is therefore positive on this interval.

So the domain can be revised to [2,∞)∪(-2,1).

Note that +2 is within the domain, because the denominator becomes zero. However, -2 and 1 are excluded because the denominator becomes zero.

- math -
**sh**, Tuesday, October 5, 2010 at 6:01pmWhen I factor out the bottom its x=-3 and x=2, how did you get -2 and 1? Why is +2 included? Doesn't it become undefined when x=2?

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