math
posted by sh on .
What's the domain of √((x2)/(x^2+x6))
(2,infinity] ?

The proposed answer is good for √(x2).
However, since the denominator becomes negative between 2 and 1, the expression in the squareroot radical is therefore positive on this interval.
So the domain can be revised to [2,∞)∪(2,1).
Note that +2 is within the domain, because the denominator becomes zero. However, 2 and 1 are excluded because the denominator becomes zero. 
When I factor out the bottom its x=3 and x=2, how did you get 2 and 1? Why is +2 included? Doesn't it become undefined when x=2?