Posted by Joe on Tuesday, October 5, 2010 at 12:10am.
Can somebody tell me what to do next for solving polynomial equations?
x^3  3x^2 4x + 12= 0
I got the factors of 12 and i used 2.
(x+2) (x^2 + x + 12)=0
What do I do next?

12th grade  Joe, Tuesday, October 5, 2010 at 12:13am
I used synthetic division to get (x+2)(x^2 + x + 12)=0

12th grade  Leanna, Tuesday, October 5, 2010 at 6:16pm
Factor x^2+x+12 now

12th grade  Joe, Tuesday, October 5, 2010 at 6:41pm
(x+4)(x+3)=0
therefore, (x+2)(x+4)(x+3)=0?
x= 2, 4, 3?

12th grade  clayton, Sunday, October 10, 2010 at 7:01pm
(x+3)(x+5)
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