Posted by **Joe** on Tuesday, October 5, 2010 at 12:10am.

Can somebody tell me what to do next for solving polynomial equations?

x^3 - 3x^2 -4x + 12= 0

I got the factors of 12 and i used 2.

(x+2) (x^2 + x + 12)=0

What do I do next?

- 12th grade -
**Joe**, Tuesday, October 5, 2010 at 12:13am
I used synthetic division to get (x+2)(x^2 + x + 12)=0

- 12th grade -
**Leanna**, Tuesday, October 5, 2010 at 6:16pm
Factor x^2+x+12 now

- 12th grade -
**Joe**, Tuesday, October 5, 2010 at 6:41pm
(x+4)(x+3)=0

therefore, (x+2)(x+4)(x+3)=0?

x= -2, -4, -3?

- 12th grade -
**clayton**, Sunday, October 10, 2010 at 7:01pm
(x+3)(x+5)

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