Posted by **Anonymous** on Monday, October 4, 2010 at 9:45pm.

a 17-foot ladder leans against a wall. if the ladder is 8 feet from the base of the wall, how far is it from the bottom of the wall to the top of the ladder

- algebra -
**Mindy**, Monday, October 4, 2010 at 9:53pm
15ft

imagine a triangle. The diagonal side is 17 ft. the bottom is 8 ft. Use the pythagorean theorem to find the third side. so

17^2 minus 8^2 = 225. then take the square root of 225, which is 15

- algebra -
**Ms. Sue**, Monday, October 4, 2010 at 9:55pm
Let c = the length of the ladder. b = the distance from the wall. Use the Pythagorean theorem.

a^2 + b^2 = c^2

a^2 + 8^2 = 17^2

a^2 + 64 = 289

a^2 = 225

a = 15

- algebra -
**Mindy**, Monday, October 4, 2010 at 9:58pm
my way worked too

- algebra -
**Ms. Sue**, Monday, October 4, 2010 at 10:06pm
Yep. It's always good to show students more than one way to solve a problem.

Btw -- I hadn't seen your post when a posted mine.

- algebra -
**Ms. Sue**, Monday, October 4, 2010 at 10:07pm
*I posted mine.

- algebra -
**Mindy**, Monday, October 4, 2010 at 10:08pm
oh ok :)

- algebra -
**Anonymous**, Sunday, May 15, 2016 at 11:23am
A ladder with length 20m. stands vertically against a wall. How much further should the lower end of the end of the ladder be moved so that its upper end descends 4 metre?

- algebra -
**Rick**, Wednesday, October 12, 2016 at 9:41pm
My 20 foot ladder was about 8 feet from the wall and by the time my face busted on the rock below I didn't do any measuring.

I drove to the hospital and got many stitches.

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