Posted by Anonymous on Monday, October 4, 2010 at 9:45pm.
a 17-foot ladder leans against a wall. if the ladder is 8 feet from the base of the wall, how far is it from the bottom of the wall to the top of the ladder
- algebra - Mindy, Monday, October 4, 2010 at 9:53pm
imagine a triangle. The diagonal side is 17 ft. the bottom is 8 ft. Use the pythagorean theorem to find the third side. so
17^2 minus 8^2 = 225. then take the square root of 225, which is 15
- algebra - Ms. Sue, Monday, October 4, 2010 at 9:55pm
Let c = the length of the ladder. b = the distance from the wall. Use the Pythagorean theorem.
a^2 + b^2 = c^2
a^2 + 8^2 = 17^2
a^2 + 64 = 289
a^2 = 225
a = 15
- algebra - Mindy, Monday, October 4, 2010 at 9:58pm
my way worked too
- algebra - Ms. Sue, Monday, October 4, 2010 at 10:06pm
Yep. It's always good to show students more than one way to solve a problem.
Btw -- I hadn't seen your post when a posted mine.
- algebra - Ms. Sue, Monday, October 4, 2010 at 10:07pm
*I posted mine.
- algebra - Mindy, Monday, October 4, 2010 at 10:08pm
oh ok :)
- algebra - Anonymous, Sunday, May 15, 2016 at 11:23am
A ladder with length 20m. stands vertically against a wall. How much further should the lower end of the end of the ladder be moved so that its upper end descends 4 metre?
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