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If a student used 11.54mL of their NaOH solution to neutralize 10.00mL of a 0.445M KHP solution, then what is the concentration of the student's NaOH solution (in Molarity)?

  • Chemistry -

    NaOH + KHP ==> NaKP + H2O

    moles KHP = M x L = ??
    moles NaOH = same (from the equation)
    M NaOH = moles NaOH/L NaOH

  • Chemistry -

    0.01L KHP * 0.445M KHP = 0.00445 molKHP
    KHP and NaOH are in 1 to 1 ratio so, moles NaOH = 0.00445
    0.00445mol NaOH/ 0.01154L NaOH = 0.386M NaOH

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