Posted by Ari on .
If a student used 11.54mL of their NaOH solution to neutralize 10.00mL of a 0.445M KHP solution, then what is the concentration of the student's NaOH solution (in Molarity)?
NaOH + KHP ==> NaKP + H2O
moles KHP = M x L = ??
moles NaOH = same (from the equation)
M NaOH = moles NaOH/L NaOH
0.01L KHP * 0.445M KHP = 0.00445 molKHP
KHP and NaOH are in 1 to 1 ratio so, moles NaOH = 0.00445
0.00445mol NaOH/ 0.01154L NaOH = 0.386M NaOH