Help please am kind of confused on this problem, am mostly confused on what state the products will be.
Find net ionic equation? I BELIEVE ITS BALANCED NOW.
2Al(s)+ 2CuCl3(aq)-> 2AlCl3(?)+ 2Cu(?)
I think I answered this with a couple of questions of my own. It is balanced now (it wasn't before) and I'm assuming you intend for the second substance to be CuCl3 (which makes Cu a +3 oxidation state and that is unusual). However, to answer your question, regardless of the oxidation number of Cu, the AlCl3 will be (aq) and the Cu on the right will be (s).
To determine the net ionic equation, we need to first write the balanced chemical equation for the given reaction. Then, we can identify the spectator ions and eliminate them to obtain the net ionic equation.
Let's start by balancing the equation:
2Al(s) + 2CuCl3(aq) → 2AlCl3(?) + 2Cu(?)
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
For the reactants, there are already two aluminum (Al) atoms on both sides. However, on the reactant side, there are six chlorine (Cl) atoms (3 from each CuCl3), while on the product side, there are only three chlorine atoms in AlCl3 (1.5 from each AlCl3). To balance the chlorine, we need to multiply AlCl3 by a factor of 2:
2Al(s) + 2CuCl3(aq) → 4AlCl3(?) + 2Cu(?)
Now we have a balanced equation.
The net ionic equation is obtained by eliminating the spectator ions, which are ions that do not participate in the overall reaction and remain unchanged. In this case, the spectator ions are the aluminum ions (Al) and the copper ions (Cu). The chloride ions (Cl) are the only ions that undergo a change, as they switch from being a part of the reactants to being a part of the products.
Thus, the net ionic equation for this reaction is:
2Cl^-(aq) + 2CuCl3(aq) → 4Cl^-(aq) + 2Cu(?)
Note that the Al ions are eliminated entirely from the equation since they are spectator ions. The Cu ions are left as "?" since their state is not given in the original equation.
Therefore, the net ionic equation for the given reaction is:
2Cl^-(aq) + 2CuCl3(aq) → 4Cl^-(aq) + 2Cu(?)