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April 16, 2014

April 16, 2014

Posted by **Dan** on Monday, October 4, 2010 at 5:10pm.

- College Physics -
**bobpursley**, Monday, October 4, 2010 at 5:18pmtotal acceleration= sqrt(1.5^2+(v^2/r)^2)

3.2^2-1.5^2=(v^2/r)^2

solve for v^2/r

then,

angvelocity^2=2*angularacceleration*angulardisplacement

(V^2/r)1/r=2*1.50/r*angulardisplacement

solve for angular displacement, divide by 2PI to get revolutions

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