Posted by Jim on .
I need to find the domain of the following function:
My math is a bit rusty after holidays...This is what I did: (I'll use <> for the sign of 'not equal')
-> 2x+1<>0 <=> 2x<>-1 <=> x <> -1/2
But i'm not sure about the rest! What I though of doing was this: the domain of arcsin(x) is [-1,1], so I could write that for the given function, ((x-3)/(2x+1)) is between -1 and 1... Not sure though...Help!