physics
posted by Frankie .
EXPLAIN
A rubber ball (mass 0.30 kg) is dropped from a height of 1.2 m onto the floor. Just after bouncing from the floor, the ball has a speed of 3.6 m/s.
(a) What is the magnitude and direction of the impulse imparted by the floor to the ball?
so to find v1=square root of 2gh
V1*m +V2*m=2.5
WHERE did the square root of 2gh come from?

Remember the equation
Vf^2=Vi^2+2gh ? If Vi is zero, then...Vf=
Where did it come from..Conservation of energy.
The final KE at impact= the intial PE
1/2 mv^2=mgh