Mathsssssssssssss
posted by john .
triangle ABC A is (3,1) B is (5,3) C is (1,7)
find the equations of:
the median AM
And
the perpendicular bisector of BC

Middle of BC is
( (1+5)/2 , (3+7)/2) )
or
(3,2) is point M
so
line through (3,1) and (3,2)
I bet you can find that line.
Then
line through M perpendicular to BC
slope of BC = 10/4 = 5/2
so slope we want = 2/5
so line with m = 2/5 that goes through (3,2)
I bet you can do that too.