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November 26, 2014

November 26, 2014

Posted by **john** on Monday, October 4, 2010 at 1:03pm.

find the equations of:

the median AM

And

the perpendicular bisector of BC

- Mathsssssssssssss -
**Damon**, Monday, October 4, 2010 at 1:41pmMiddle of BC is

( (1+5)/2 , (-3+7)/2) )

or

(3,2) is point M

so

line through (-3,1) and (3,2)

I bet you can find that line.

Then

line through M perpendicular to BC

slope of BC = 10/-4 = -5/2

so slope we want = 2/5

so line with m = 2/5 that goes through (3,2)

I bet you can do that too.

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