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October 30, 2014

Homework Help: chemistry

Posted by Anonymous on Monday, October 4, 2010 at 12:54pm.

can someone help me with this please? i've been stuck on this one forever...

A solution is made by mixing 25.0 mL of toluene C6H5CH3d=0867gmL with 135.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are

M and m.

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