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August 1, 2014

August 1, 2014

Posted by **Bala** on Monday, October 4, 2010 at 11:20am.

What is her average velocity for the trip?

- Physics -
**tchrwill**, Monday, October 4, 2010 at 5:35pm"Average" speed results from dividing the total distance by the total time.

Using V = D/T

The distance covered during the 1st part is 22x6.6mi.

The distance covered during the 2nd part is 36x5.4mi.

The distance covered during the 3rd part is 8x14.4mi.

Therefore, her "average" speed is (D1 + D2 + D3)/(T1 + T2 + T3)

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