posted by Wendia on .
A 3.9 kg particle starts from rest and moves a
distance of 2.4 m in 2.4 s under the action of
a single, constant force.
Find the magnitude of the force.
Answer in units of N.
X = (1/2) a t^2 = (1/2)(F/M)*t^2
X = 2.4 m is the distance it moves
a is the acceleration. which equals F/M
t = 2.4 s
Solve for F in Newtons
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