posted by amber on .
How many grams of KCl are required to make .75 L of 0.29 M solution? Round to one decimal place.
i got .2907
is this correct
im not sure about the decimal places
Try to remember to include leading zeros as this are easily lost. So 0.75 rather than .75
MM of KCl is 74.5513 g/mol
so number of moles is
74.5513 g/mol c 0.75 litre x 0.20 mol litre^-1
which rounds to 11.2 g to 1 decimal place.
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