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chemistry

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How many grams of KCl are required to make .75 L of 0.29 M solution? Round to one decimal place.

i got .2907
is this correct
im not sure about the decimal places
thanks

  • chemistry - ,

    massingrams=molmassKCl*.75*.29

  • chemistry - ,

    Try to remember to include leading zeros as this are easily lost. So 0.75 rather than .75

    MM of KCl is 74.5513 g/mol

    so number of moles is

    74.5513 g/mol c 0.75 litre x 0.20 mol litre^-1

    =11.182 g

    which rounds to 11.2 g to 1 decimal place.

    You might find this site useful

    http://www.cimt.plymouth.ac.uk/projects/mepres/book7/bk7i2/bk7_2i2.htm

    for rounding.

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