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August 2, 2014

Homework Help: chemistry

Posted by amber on Monday, October 4, 2010 at 8:49am.

Oxalic acid (H2C2O4) can be used to remove rust according to the following balanced equation:

Fe2O3 + 6H2C2O4 --> 2Fe(C2O4)33- +3H2O + 6H+

Calculate the number of grams of rust that can be removed by 5.00 x 102 ml of a 0.122M solution of oxalic acid.


I know i need to multiply the # of moles*6*160 (which is the molecular mass)
.5z*.122=
0.061 moles of oxalic acid.
so is it .061*6*160= 585.6
is that right i'm pretty sure its not

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