Posted by Shaila on Monday, October 4, 2010 at 8:41am.
First solve for the speed of the cars locked together, V', using the fact that the kinetic energy lost equals work done against friction during the skid.
(1/2)(M+m)V'^2 = (M+m)(Uk)*g*X
V'^2 = 2*0.750*9.8*4.58 = 63.3 m/s^2
Then apply conservation of momentum to determine the speed of the faster car that caused the collision, V.
M V = (M+m)*V'
Solve for V
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