I need to find the ionic equation of:
3Ba(OH)2(aq)+2H3PO4(aq)->Ba3(PO4)2+6H20(l)
I'm totally lost on this question
Are you looking for total net equation?
To determine the ionic equation for the given reaction, you need to first write the balanced molecular equation and then break down the reactants and products into their respective ions.
The balanced molecular equation is:
3 Ba(OH)2(aq) + 2 H3PO4(aq) -> Ba3(PO4)2(s) + 6 H2O(l)
Now, let's break down the reactants and products into ions:
Ba(OH)2(aq) dissociates into: 3 Ba2+(aq) + 6 OH-(aq)
H3PO4(aq) dissociates into: 2 H+(aq) + 3 PO43-(aq)
Ba3(PO4)2(s) remains unchanged
H2O(l) remains unchanged
Next, we need to identify the ions that participate in the reaction. In this case:
- Ba2+ reacts with the PO43- ion to form Ba3(PO4)2(s)
- OH- reacts with H+ to form H2O
Therefore, the ionic equation for this reaction is:
3 Ba2+(aq) + 6 OH-(aq) + 2 H+(aq) + 3 PO43-(aq) -> Ba3(PO4)2(s) + 6 H2O(l)
I hope this helps! Let me know if you have any further questions.
To find the ionic equation for the given chemical reaction, we need to first start by writing out the molecular equation.
The given molecular equation is:
3Ba(OH)2(aq) + 2H3PO4(aq) -> Ba3(PO4)2 + 6H2O(l)
Now, let's break down each compound into their respective ions. We can identify the ions based on their solubility rules. Here are the compound breakdowns:
Ba(OH)2(aq):
Ba2+(aq) + 2OH-(aq)
H3PO4(aq):
H+(aq) + H2PO4-(aq)
Ba3(PO4)2:
Ba2+(aq) + 2PO43-(aq)
H2O(l):
H2O is a molecular compound, so we don't need to break it down into ions.
Now that we have broken down the compounds into ions, we can write the complete ionic equation by representing the compounds in their ionized form. The solid substances (such as Ba3(PO4)2) are written as complete, undissociated compounds. The soluble substances (such as Ba(OH)2 and H3PO4) are written as the dissociated ions:
Complete ionic equation:
3Ba2+(aq) + 6OH-(aq) + 2H+(aq) + 2H2PO4-(aq) -> Ba3(PO4)2(s) + 6H2O(l)
Lastly, we can simplify the equation by eliminating the spectator ions. Spectator ions are ions that appear on both sides of the equation and do not participate in the reaction. In this equation, the spectator ions are the OH- ions.
Therefore, the simplified ionic equation is:
3Ba2+(aq) + 2H2PO4-(aq) -> Ba3(PO4)2(s) + 6H2O(l)
This is the ionic equation for the given chemical reaction.
3Ba2+(aq)+2OH-(aq)+6H+(aq)+2(PO4)3-====>Ba3(PO4)2(s) + 6H2O
You separate the elements, then if there is a reaction you end up with a Net equation, because this has H20 and an solid Ba3(PO4)2 the net equation it the same as the ionic, you can't break apart a solid or H2O. The charges should be on the right hand side on top of the element, along with the state below in parenthesis. All of the reactants are aqueous, which mean they can be divided but, because the product isn't nothing gets left out. Hope this helps.