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April 25, 2014

Posted by **Jessica** on Monday, October 4, 2010 at 12:57am.

16x^7y^12-10X^5y^8/2x^2y^9

- math -
**KELLY**, Monday, October 4, 2010 at 1:07am16x^7y^12-10X^5y^8/2x^2y^9

=(16x^7y^12/2x^2y^9)-(10x^5y^8/2x^2y^9)

=((16/2)*x^(7-2)*y^(12-9))-((10/2)*x^(5-2)*y^(8-9))

=8x^5y^3-5x^3y^-1

or

=(8x^5y^3)-((5x^3)/y)

- math -
**PsyDAG**, Monday, October 4, 2010 at 1:09pmTo make problem clearer, you need to include parentheses.

Do you mean:

(16x^7y^12-10X^5y^8)/(2x^2y^9)

or

16x^7y^12-(10X^5y^8)/(2x^2y^9)?

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