Homework Help: college chemistry

Posted by sparkle on Sunday, October 3, 2010 at 11:01pm.

The value of the equilibrium constant (Kp) as represented by the first chemical equation is 4.57 x 10-2 at 395 °C. Calculate the value of the equilibrium constant (Kp) for the second equation at the same temperature. Express answer in scientific notation.

Cl2CO(g) = CO(g)+Cl2(g)

CO(g)+Cl2(g) = Cl2CO(g)

college chemistry - DrBob222, Sunday, October 3, 2010 at 11:22pm
The second equation is just the reverse of the first equation; therefore, the Kp for the second equation is the reciprocal of Kp for the first one given; i.e.,
Kp2 = (1/4.57 x 10^-2) = ??

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