Posted by Elizabeth on Sunday, October 3, 2010 at 10:11pm.
A car is traveling at 54.2 km/h on a flat highway. The acceleration of gravity is 9.81 m/s^2.
PART 1: If the coefficient of kinetic friction between the road and the tires on a rainy day is 0.131, what is the minimum distance needed for the car to stop? Answer in unitsof m.
PART 2: What is the stopping distance when the surface is dry and the coefficient of kinetic friction is 0.603? Answer in units of m.

Physics  MathMate, Sunday, October 3, 2010 at 10:55pm
Frictional resistance, F
= μ mg
acceleration, a
= F/m
= μg
For distance S, use
v²u²=2aS
where v=final velocity =0
u=initial velocity = 54.2 km/h = 15.06 m/s
Solve for S.
1. μ=0.131
u=54.2
a=0.131*9.8=1.284 m/s²
S=15.06²/(2*1.284)
=88.3m
The same approach can be used for both cases.
Post your answers for a check if you wish.

Physics  Elizabeth, Sunday, October 3, 2010 at 11:06pm
omg thx so much!!!!
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