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August 2, 2014

August 2, 2014

Posted by **Kyo** on Sunday, October 3, 2010 at 9:14pm.

2NH3(g) = N2(g)+3H2(g)

- Chemistry -
**DrBob222**, Sunday, October 3, 2010 at 11:14pminitial pressure NH3 = 0.7317 atm.

initial pressure H2 = 0 and N2 = 0

At equilibrium

N2 = x

H2 = 3x

NH3 = 0.7317 - 2x

Kp = 67,100 = pN2*pH2^3/pNH3^2

Substitute into Kp and solve for x, then convert to NH3, H2, N2.

Finally, pNH3 remaining (from above) to percent of original amount present.

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