A spider has 8 legs. An ant has 6 legs. There are a group of spiders and a group of ants. The groups have equal numbers of legs. What is the least number of spiders and ants in each group.

The least common multiple of 8 and 6 is 24.

24/8 = 3 spiders
24/6 = 4 ants

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To find the least number of spiders and ants in each group such that the total number of legs in both groups is equal, we need to determine the lowest common multiple (LCM) of 8 and 6.

The LCM is the smallest number that is divisible by both 8 and 6. We can find the LCM using several methods, but one simple approach is to list the multiples of each number until we find a common multiple.

Multiples of 8: 8, 16, 24, 32, 40, 48, 56, 64, ...

Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, ...

From the lists above, 24 is the smallest number that appears in both lists. Therefore, the LCM of 8 and 6 is 24.

Since the LCM represents the total number of legs in each group, we can divide it by the number of legs per spider and the number of legs per ant to find the minimum number of spiders and ants in each group.

Number of spiders = LCM / Number of legs per spider = 24 / 8 = 3

Number of ants = LCM / Number of legs per ant = 24 / 6 = 4

Hence, the least number of spiders and ants in each group is 3 and 4, respectively, to ensure that both groups have an equal number of legs.

The least common multiple is8 and 6 is 24 ther pe are 3 spiders and 4 ants

Is the Answer 24??

thanks

what the answer????

The answer