Researchers have found that a gecko's foot is covered with hundreds of thousands of small hairs (setae) that allow it to walk up walls and even across ceilings. A single foot pad, which has an area of , can attach to a wall or ceiling with a force of 11 .
How many 250- geckos could be suspended from the ceiling by a single foot pad?
Your use of numerials for units makes it impossbile to decipher. 11 what? 250 what? and area of ?
11 N.
250 grams
1.0 cm2
The 1.0cm2 is the area of the single foot pad.
To find out how many 250-geckos could be suspended from the ceiling by a single foot pad, we need to consider the force that the foot pad can generate and the weight of each gecko.
We know that the force generated by the foot pad is 11 . This force is supporting the weight of the gecko.
Now, to determine the weight of each gecko, we need to use the formula:
Weight = Mass × Acceleration due to gravity
The problem doesn't provide the mass of each gecko, but we are given that they weigh 250- each. However, we can assume that the weight mentioned is the mass in grams. We'll convert it to kilograms by dividing by 1000.
Weight = 250- ÷ 1000 = 0.25 kg
The acceleration due to gravity on Earth is approximately 9.8 m/s².
Now, we can use the formula:
Force = Weight × Acceleration due to gravity
11 = Weight × 9.8
Solving for Weight:
Weight = 11 ÷ 9.8 = 1.12 kg
We have determined that the weight of each gecko is 1.12 kg.
To calculate the number of geckos that can be suspended, we need to divide the force generated by the foot pad by the weight of each gecko:
Number of geckos = Force generated by foot pad ÷ Weight of each gecko
Number of geckos = 11 ÷ 1.12 ≈ 9.82
Therefore, a single foot pad can suspend approximately 9 geckos of 250- each from the ceiling.