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Oxalic acid (H2C2O4) can be used to remove rust according to the following balanced equation:

Fe2O3 + 6H2C2O4 --> 2Fe(C2O4)33- +3H2O + 6H+

Calculate the number of grams of rust that can be removed by 5.00 x 102 ml of a 0.122M solution of oxalic acid.

  • chemistry - ,

    My first thought is since when is rust IronIII oxide?
    Ok, how many moles of oxalic acid?
    moles=.500l*.122=you do it.

    Now, moles of IronIIIoxide=moleacid *6)

    Then, convert moles of ironIII oxide to grams.

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