Thursday

July 31, 2014

July 31, 2014

Posted by **Anna** on Sunday, October 3, 2010 at 12:11am.

I know that I would start with

f'(x)=2((x^2+3)^5+x) but I don't know how to do the rest

- Calculus -
**Anna**, Sunday, October 3, 2010 at 12:14amThe answer is

f'(x)=2((x^2+3)^5+x)[5(x^2+3)^4(2x)+1]

I don't understand where the +1 at the end comes from

**Related Questions**

Calculus - y= [(x-3)/(x^2+1)]^2 find the derivative. I know i would start off ...

MoRe HeLp PlEaSe!! (calc) - Also can I get some help with this LONG, TIRESOME ...

calculus - Please help. Applying the chain rule, how do I find the derivative of...

Calculus - How do I use the chain rule to find the derivative of square root(1-x...

CAlculus - using chain rule find the derivative of y=xsin1/x

Math - Calculus Question. - hey can someone explain to me the relationship ...

Applied Calculus - Find the derivative of this function: g(t)=(8t+10)^2*(10t^2-7...

calculus-derivatives - y=cos^3(12theta) find derivative using chain rule

Calculus - Find the derivative: h(x)=7x/sqrt(5-2x) Using the chain rule...I ...

Math, Calculus - Find the derivative of the function. y= xcosx - sinx What's the...