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Calculus

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find the derivative of f(x)=((x^2+3)^5+x)^2 using the chain rule.

I know that I would start with
f'(x)=2((x^2+3)^5+x) but I don't know how to do the rest

  • Calculus - ,

    The answer is

    f'(x)=2((x^2+3)^5+x)[5(x^2+3)^4(2x)+1]

    I don't understand where the +1 at the end comes from

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