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August 1, 2014

August 1, 2014

Posted by **APpreciate student** on Saturday, October 2, 2010 at 4:44pm.

Thank you very much!

f(x) = (1/x) + ln(x)

f'(X) = ln|x| + (1/x)

0 = ln|x| + (1/x)

how do I solve for x??

Thanks again :)

- calc -
**Reiny**, Saturday, October 2, 2010 at 5:47pmyour derivative is incorrect,

the derivative of 1/x is -1/x^2 , not lnx

so f'(x) = -1/x^2 + 1/x

-1/x^2 + 1/x = 0

multiply by -x^2

1 - x = 0

x =1

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