physics
posted by Anonymous .
way performance, an 95.6 kg actor swings from a 4.30 m long cable that is horizontal when he starts. At the bottom of his arc, he picks up his 55.0 kg costar in an inelastic collision. What maximum height do they reach after their upward swing?

calculate speed at bottom from:
(1/2) m v^2 = m g h
where h is 4.30 and m cancels and g = 9.81
95.6 * v = (95.6+55) * v after
(1/2) * new m * v after^2 = new m * g * h
again new m cancels. It only mattered for conservation of momentum