posted by zero .
If 220. mL of 0.1364 M aqueous LiOH and 0.3553 L of gaseous CO2 measured at 1.36 atm pressure and 360 K are reacted stoichiometrically according to the equation, what mass (g) of gaseous CO2 remained?
2 LiOH(aq) + CO2(g) → Li2CO3(aq)
moles LiOH = M x L.
Using the coefficients in the balanced equation, convert moles LiOH to moles CO2 used in the reaction.
Now use PV = nRT to calculate moles CO2 initially, subtract moles CO2 used (from above), then convert moles CO2 remaining to grams. g = moles x molar mass.
Post your work if you get stuck.