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If 220. mL of 0.1364 M aqueous LiOH and 0.3553 L of gaseous CO2 measured at 1.36 atm pressure and 360 K are reacted stoichiometrically according to the equation, what mass (g) of gaseous CO2 remained?

2 LiOH(aq) + CO2(g) → Li2CO3(aq)

  • chemistry -

    moles LiOH = M x L.
    Using the coefficients in the balanced equation, convert moles LiOH to moles CO2 used in the reaction.

    Now use PV = nRT to calculate moles CO2 initially, subtract moles CO2 used (from above), then convert moles CO2 remaining to grams. g = moles x molar mass.
    Post your work if you get stuck.

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